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日期轉(zhuǎn)為星期顯示的SQL

 昵稱10504424 2013-03-15

根據(jù)月份得出日歷,求一sql 
日       一       二       三       四       五       六      
            
1         2        3       4        5         6          
 7          8         9      10     11     12       13      
14       15       16     17     18     19       20      
21       22       23     24     25     26       27      
28       29       30     31      

像這樣的
---------------------------------------

declare @month as varchar(7)
set @month = '2007-12'

select 日,一,二,三,四,五,六 from
(
select week ,
 
max(case weekday when 1 then datename(day,dt) else '' end ) '',
 
max(case weekday when 2 then datename(day,dt) else '' end ) '',
 
max(case weekday when 3 then datename(day,dt) else '' end ) '',
 
max(case weekday when 4 then datename(day,dt) else '' end ) '',
 
max(case weekday when 5 then datename(day,dt) else '' end ) '',
 
max(case weekday when 6 then datename(day,dt) else '' end ) '',
 
max(case weekday when 7 then datename(day,dt) else '' end ) ''
from
(
 
select week = datepart(week , m.dt) , weekday = datepart(weekday , m.dt) , dt from
  (
   
select dt = @month + '-' + right('00'+cast(t.id as varchar),2) from
    (
     
select 1 as id union select 2 union select 3 union select 4 union select 5
     
union select 6 union select 7 union select 8 union select 9 union select 10
     
union select 11 union select 12 union select 13 union select 14 union select 15
     
union select 16 union select 17 union select 18 union select 19 union select 20
     
union select 21 union select 22 union select 23 union select 24 union select 25
     
union select 26 union select 27 union select 28 union select 29 union select 30
     
union select 31
    ) t
   
where isdate(@month + '-' + right('00'+cast(t.id as varchar),2)) = 1 and @month + '-' + right('00'+cast(t.id as varchar),2) <= dateadd(month , 1 , @month + '-01')
  ) m
) n
group by week
) o
/*
日  一  二  三  四  五  六                             
--  --  --  --  --  --  --
                        1
2   3   4   5   6   7   8
9   10  11  12  13  14  15
16  17  18  19  20  21  22
23  24  25  26  27  28  29
30  31                                                                                                                                                        

(所影響的行數(shù)為 6 行)
*/




----------------------------------------------------------------------
用函數(shù)解決。(libin_ftsafe)
create function f_calendar(@year int,@month int)
returns @t table(日 varchar(4),一 varchar(4),二 varchar(4),三 varchar(4),四 varchar(4),五 varchar(4),六 varchar(4))
as
begin

   
declare @a table(id int identity(0,1),date datetime)
   
   
insert into @a(date)
   
select top 31 rtrim(@year)+'-'+rtrim(@month)+'-1' from sysobjects
   
   
update @a set date=dateadd(dd,id,date)   

   
insert into @t
   
select
       
max(case datepart(dw,date) when 7 then rtrim(day(date)) else '' end),
       
max(case datepart(dw,date) when 1 then rtrim(day(date)) else '' end),
       
max(case datepart(dw,date) when 2 then rtrim(day(date)) else '' end),
       
max(case datepart(dw,date) when 3 then rtrim(day(date)) else '' end),
       
max(case datepart(dw,date) when 4 then rtrim(day(date)) else '' end),
       
max(case datepart(dw,date) when 5 then rtrim(day(date)) else '' end),
       
max(case datepart(dw,date) when 6 then rtrim(day(date)) else '' end)
   
from
       
@a
   
where
       
month(date)=@month
   
group by
        (
case datepart(dw,date) when 7 then datepart(week,date)+1 else datepart(week,date) end)

   
return
end
go

set datefirst 1
select * from dbo.f_calendar(2007,12)
/*
日    一    二    三   四    五    六   
---- ---- ---- ---- ---- ---- ----
                                            1
 2      3     4     5     6     7      8
 9    10   11   12   13  14    15
16   17   18   19   20   21   22
23   24   25   26   27   28   29
30   31                 
*/
go

drop function f_calendar
go


源:http://topic.csdn.net/u/20090321/12/81433b7d-d02a-4a88-9e59-4463d1d56da9.html#replyachor

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